bonjour
1/
perimetre d un rect = (L+l) x2
p = (4V18+10+3V32 -10) x2
p (4V3²x2 +10 +3 V4²x2 -10) x 2
p = (12V2 +12V2 ) x2
p = (24V2) x2
p = 48V2
2/
aire d un carre = cote ²
donc
p = (3V13-1)² +(3+V13)²
p = 3²(V13)² - 6V13 +1 + 9 +6V13 +13
p = 9(13) +10+13
p =117+23 =140