bonsoir
9 x² = 6 x - 1
9 x² - 6 x + 1 = 0
( 3 x - 1)² = 0
( 3 x - 1) ( 3 x - 1) = 0 ⇒ 3 x = 1 et x = 1/3
a² = 7
a = √7 ou - √7
4 x² + 12 x = - 9
4 x² + 12 x + 9 = 0
( 2 x + 3)² = 0
( 2 x + 3) ( 2 x + 3) = 0 donc 2 x = - 3 et x = - 3/2
4 a² = 3
a² = 3/4
a = √3/4 ou - √3/4
a² = - 3 pas de solution
a² = 0
a = 0
