bonjour
b) la mesure de l'angle TUS=TS/SU
tan=6/6=1
arctan(1)=45°
c)sin=ST/TU
sin 45=6/TU
6/sin(45)=6√2≈8.5 cm
d) cos TUS=SU/TU=6/8.5=0.7058823
arccos(0.7058823)=45,09913213≈45°
sin TUS=TS/TU=6/8.5=0.7058823
arcsin(0.7058823)=44.90086787≈45°
tan TUS=6/6=1
arctan(1)=45°