Bonjour,
f(1) f(-1) et f(2)
f(x) = 3/(x + 5)
f(1) = 3/(1 + 5) = 3/6 = 1/2
f(-1) = 3/(-1 + 5) = 3/4
f(2) = 3/(2 + 5) = 3/7
f(x) = 3/x + 5
f(1) = 3/1 + 5 = 3 + 5 = 8
f(-1) = 3/-1 + 5 = -3 + 5 = 2
f(2) = 3/2 + 5 = 3/2 + 10/2 = 13/2
f(x) = (x + 2)/x
f(1) = (1 + 2)/1 = 3
f(-1) = (-1 + 2)/-1 = -1
f(2) = (2 + 2)/2 = 4/2 = 2
f(x) = √(x + 3)
f(1) = √(1 + 3) = √4 = 2
f(-1) = √(-1 + 3) = √2
f(2) = √(2 + 3) = √5
