1) Pc : périmètre coloré
P =2πr/2 = πxr = 3.14x0.03 = 0.0942 m
P1 = P2 = 2πxr1/2 = πxr1 = 3.14x0.03/2 = 0.0471 m
FH = D = 2r
T centre du demi-cercle donc FT = FH
2P1 = 0.0942
Pc = 0
2) Aire du demi-cercle est : πD^2/8 = 3.14 x0.06^2/8 = 0.001413 m2
A1 = A2 = πD1^2/8 = 3.14x0.03^2/8 = 0.00035325 m2
2A1 = 0.0007065 m2
Ac = A - 2A1 = 0.001413 - 0.0007065 = 0;0007065 m2
Arrondis au centième près Ac =0.07 m2
