Bonjour,
1)
[tex]f(x) = (3x-4)^2-(3x+3)^2\\
\Rightarrow a^2-b^2 = (a-b)(a+b)\\ = (3x-4-(3x+3))(3x-4+(3x+3))\\ = (3x-4-3x-3)(3x-4+3x+3)\\ = (-7)(6x-1)\\
-7(6x-1)[/tex]
2)
[tex]f(x) = -7(6x-1)\\
= -42x+7[/tex]
3)
[tex]f(-2) = -7(6\times(-2)-1)\\
= -7(-12-1)\\
= -7(-13)\\
= 91[/tex]
4)
[tex]f(x) = 0\\
-7(6x-1) = 0\\
6x-1 = 0\\
6x=1\\\\
x = \dfrac{1}{6}[/tex]
Bonne journée et bon courage.