Bonsoir,
[tex]6\times\left(\dfrac{1}{3} \right)^2 - 7\times\left(-\dfrac{1}{3}\right)-3\\\\\\
= 6\times \dfrac{1^2}{3^2} - \dfrac{-7\times 1}{3} - \dfrac{3}{1}\\\\
= \dfrac{6}{9} + \dfrac{7}{3} - \dfrac{3}{1}\\\\
= \dfrac{6}{9} + \dfrac{7\times 3}{3\times 3} - \dfrac{9\times 9}{1\times 9}\\\\
= \dfrac{6}{9} + \dfrac{21}{9} - \dfrac{27}{9}\\\\=\dfrac{27}{9}-\dfrac{27}{9}\\\\=0[/tex]
