A= (2x-5)(2x-5) - (5-x)(2x+3)
= 4x² - 20x + 25 - 10x + 15 - 2x² - 3x
= 2x² - 33x + 40
B= [tex] \frac{-5}{6} + \frac{-7*-2}{3*5} [/tex]
= [tex] \frac{-5}{6} + \frac{14}{15} [/tex]
= [tex] \frac{-5*5}{6*5} + \frac{14*2}{15*2}
= \frac{-25}{30} + \frac{28}{30} = \frac{3}{30} [/tex]
C= [tex] \frac{-7}{5} / ( \frac{-9*3}{4*3} - \frac{1*2}{6*2} ) = \frac{-7}{5} / ( \frac{-27}{12}- \frac{2}{12}) = \frac{-7}{5} / \frac{-25}{12} = \frac{-7}{5} * \frac{12}{-25} = \frac{-84}{-125} [/tex]
