Bonsoir,
Voilà,J’ai calculer 3 et Je vous laisse la dernière (même méthode) :)[tex]\frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\[tex] \\ \\ \frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\ \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex][tex] \\ \\ \frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\ \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex] \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex][tex]\frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\ \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex]
[tex]\frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\ \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex][tex] \\ \\ \frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\ \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex]
