Bonsoir,
7√18➗2√3✖️3√2 =
[tex]\frac{7\sqrt18}{2\sqrt3} \times 3\sqrt2[/tex]
[tex]7\sqrt18 = 7\sqrt(2 \times 3^{2}} = 21\sqrt2[/tex]
[tex]21\sqrt2 \times 3\sqrt2 = 21 \times 3 \times (\sqrt2)^{2} = 63 \times 2 = 126[/tex]
[tex]\frac{126}{2\sqrt3} = \frac{63}{\sqrt3} = \frac{63\sqrt3}{(\sqrt3)^{2}} = \frac{63\sqrt3}{3} = 21\sqrt3[/tex]
