Bonjour,
[tex]u_{n+1}=a*u_n+b\\v_n=u_n+c\\\quad\ \\v_{n+1}=u_{n+1}+c\\\quad\ =a*u_n+b+c\\\quad\ =k*v_n\\\quad\ =k*(u_n+c)\\\Longrightarrow\ k*u_n+k*c=a*u_n+b+c\\\Longrightarrow\ k=a\ et\ kc=b+c\\\Longrightarrow\ k=a\ et\ c=\dfrac{b}{k-1}\\\Longrightarrow\ \boxed{ c=\dfrac{b}{a-1}}\\[/tex]