1) [tex]\frac{x^{2} }{2-x}>1\\ x^{2} > 2-x\\x^{2} +x> 2[/tex]
x<-2 ou x>1
2) [tex]\frac{6}{9-x^{2} } +2\leq \frac{1}{3+x^{2} } \\\frac{6+18-2x}{(3-x)(3+x) } \leq \frac{1}{3+x^{2} } \\\\24-2x\leq \frac{(3-x)(3+x)}{(3+x)}\\ 24-2x\leq 3-x\\21\leq -3x\\x\leq -7[/tex]
