Est ce que quelqu’un pourrait m’aider pour l’exercice 8 svp ? Merci d’avance...

Bonsoir
exercice 8
N = (3x-5)(2x-1)-4(x-1)
N = 6x² - 3x -10x + 5 - 4x + 4
N = 6x² - 17x + 9
2a
N = 6×0²-17×0+9
N = 9
2b.
N = 6×(-1)²-17×(-1)+9
N = 6+17+9
N = 32
2c.
N = (3×½-5)(2×½-1) - 4(½-1)
N = (3×½-5)(1-1) - 4(-½)
N = (3×½-5)×0 - 4(-½)
N = 2
2d
N = (3Ă—â…”-5)(2Ă—â…”-1) - 4(â…”-1)
N = ( 2-5)(4/3 -1 ) -4(-â…“)
N= -3(â…“) + 4/3
N = -1 + 4/3
N = 1/3