Bonjour Garydesir1
[tex]A= x^3-16x=x(x^2-16)=x(x^2-4^2)\\\boxed{A=x(x+4)(x-4)}[/tex]
[tex]B=( 2x+7)(x-4)+(x-4)= (x-4)[( 2x+7)+1] \\= (x-4)( 2x+7+1)= (x-4)( 2x+8)\\\boxed{B=2(x-4)(x+4)}[/tex]
[tex]C= ( 1-4x)^2-( 4-x )^2=[ ( 1-4x)+( 4-x )][ ( 1-4x)-( 4-x)]\\=( 1-4x+ 4-x )( 1-4x- 4+x)=(5-5x)(-3x-3)\\=-5(x-1)\times(-3)(x+1)\\\boxed{C=15(x-1)(x+1)}[/tex]
[tex]D= 9x^2- 12x + 4\\\boxed{D=(3x-2)^2}[/tex]
