Bonjour ,
1/
[ (2x-1) / (x+3) ] - [ (5x-4) / 5x ] = 0
[ (2x-1) / (x+3) ] = [ (5x-4) / 5x ]
(2x-1) (5x) = (5x-4) (x+3)
10x² - 5x = 5x² + 15x - 4x - 12
10x² - 5x = 5x² + 11x - 12
10x² - 5x - 5x² - 11x + 12 = 0
5x² - 16x + 12 = 0
Δ = b² - 4ac
Δ = 256 - 240
Δ = 16
x₁ = -b+√Δ/2a
x₁ = -(-16)+√16/2×5
x₁ = 16 + 4 / 10
x₁ = 20/10
x₁ = 2
x₂ = -b-√Δ/2a
x₂ = -(16)-√16/2×5
x₂ = 16 - 4 / 10
x₂ = 12/10
x₂ = 6/5
* Je te laisse faire la 2 !! :)
