Bsr,
B) Factoriser
Je suppose que c'est A = (2x+3)²+(x-5)(2x+3)
donc
A = (2x+3)²+(x-5)(2x+3)
= (2x+3)(2x+3) + (x-5)(2x+3) facteur commun : (2x+3)
= (2x+3) [(2x+3)+(x-5)]
= (2x+3)(3x-2)
Je suppose que c'est B = (x-1)(2x+5) + (x-1)²
donc :
B = (x-1)(2x+5) + (x-1)²
= (x-1)(2x+5) + (x-1)(x-1) facteur commun : (x-1)
= (x-1) [(2x+5)+(x-1)]
= (x-1) (3x+4)
Exercice 4 :
A = 7/15 - 4/15 * 5/8
= 7/15 - (4*5)/(15*8)
= 7/15 - 20/120
= (7*8)/(15*8) - 20/120
= 56/120 - 20/120
= 36 / 120
= (3*12) / (10*12)
= 3/10
B = (2 - 1/3) / (1/2 - 1/4)
= (6/3 - 1/3) / (2/4 - 1/4)
= (5/3) / (1/4)
= (5/3) * 4
= 20/3
C = (2/5 + 8/15) / (4/7 - 5/21)
= (6/15 + 8/15) / (12/21 - 5/21)
= (14/15) / (7/21)
= (14/15) * (21/7)
= 294 / 105
= (14*21) / (5*21)
= 14/5