bonjour
suite arithmétiques de R=101
u((n+1)=u(n)+100
u(n+2)=u(n+1)+101=u(n)+2(101)
u(7)=u(o)+7(101)
u(7)=u(o)+707
u(7)=7552
u(o)+707=7552
u(0)=7552-707
u(o)=6845
vérifions
u(0)=6845
u(1)=6845+101=6946
u(2)=6946+101=7047
u(3)=7047+101=7148
u(4)=7148+101=7249
u(5)=7249+101=7350
u(6)=7350+101=7451
u(7)=7451+101=7552