Bonsoir !!
A = [(x/4) + (1/3)][(x/2) - (1/3)]
A = [(3x + 4)/12][(3x - 2)/6]
A = (3x + 4)(3x - 2) / (12 × 6)
A = (9x² - 6x + 12x -8) / 72
A = (9x² + 6x - 8) / 72
B = [(x/3) - (1/4)][(x/3) + (1/4)]
B = [(4x - 3)/12][(4x + 3)/12]
B = (16x² + 12x - 12x - 9) / (12 × 12)
B = (16x² - 9) / 144
C = [(2/3)x + 1]²
C = (2/3)²x² + (4/3)x + 1
C = (4/9)x² + (4/3)x + 1
C = (4x² + 12x + 9)/ 9
D = (6/5)x × [(15/2)x + 5/4] - (3/2)x
D = (6x/5) × (30x + 10)/4 - (3/2)x
D = (180x² + 60x)/20 - (3x/2)
D = (180x² + 60x - 30x) / 20
D = (180x² + 30x) / 20
je pense il y a pas des fautes.
