Bonjour,
1)
E = (x - 2) (2x + 3) - 3 (x - 2)
E = 2x² + 3x - 4x - 6 - 3x + 6
E = 2x² - 4x
2)
E = (x - 2) (2x + 3) - 3 (x - 2)
E = (x - 2) [(2x + 3) - 3]
E = (x - 2) (2x)
E = 2x (x - 2)
Donc E = 2F
3)
2x (x - 2) = 0
2x = 0 ou x - 2 = 0
x = 0 x = 2
Les solutions sont : (0 ; 2)