Bonjour,
[tex]-0,5x^2+18x-64=0\\\\\dfrac{-0.5x^2+18x-64}{0.5}=\dfrac{0}{0.5}\\\\-x^2+36x-128=0\\x^2-36x+128=0\\x^2-4x-32x+128=0\\x(x-4)-32(x-4)=0\\(x-4)(x-32)=0\\\\x-4=0\quad ou\quad x-32=0\\x=4\quad ou \quad x=32\\\\\boxed{S=\left\{4;32\right\}}[/tex]
