Bonsoir,
[tex]A = (-4 + 3 \times \frac{2}{7}) : \frac{3}{14}[/tex]
[tex]A = (-4 + \frac{6}{7}) \times \frac{14}{3}[/tex]
[tex]A = (\frac{-28}{7} + \frac{6}{7}) \times \frac{14}{3}[/tex]
[tex]A = \frac{-22}{7} \times \frac{14}{3}[/tex]
[tex]A = \frac{-44}{3}[/tex]
[tex]B = \frac{4 - (2 - 5)^{2}}{4 + 5}[/tex]
[tex]B = \frac{4 - (-3)^{2}}{9}[/tex]
[tex]B = \frac{4 - 9}{9}[/tex]
[tex]B = \frac{-5}{9}[/tex]
[tex]C = (\frac{3}{2})^{2} - \frac{1}{3} \times \frac{-5}{2}[/tex]
[tex]C = \frac{9}{4} + \frac{5}{6}[/tex]
[tex]C = \frac{27}{12} + \frac{10}{12}[/tex]
[tex]C = \frac{37}{12}[/tex]
Je te laisse faire la D
