Réponse :
Explications étape par étape
Bonsoir
factoriser:
A(t)=(3t+1)² -(4t-1)²
A(t) = (3t + 1 - 4t + 1)(3t + 1 + 4t - 1)
A(t) = (-t + 2)(7t)
A(t) = 7t(-t + 2)
B(t)=9(t+1)²-4(2t+3)² (je suppose qu’il manque un carré ?)
B(t) = [3(t + 1) - 2(2t + 3)][3(t + 1) + 2(2t + 3)]
B(t) = (3t + 3 - 4t - 6)(3t + 3 + 4t + 6)
B(t) = (-t - 3)(7t + 9)
C(t)=t² +2t+1+(t+1)(3t-5)
C(t) = (t + 1)² + (t + 1)(3t - 5)
C(t) = (t + 1)(t + 1 + 3t - 5)
C(t) = (t + 1)(4t - 4)
C(t) = 4(t + 1)(t - 1)
D(t)=(2t+1)² +4t² - 1 je suppose qu’il manque encore un carré ?)
D(t) = (2t + 1)² + 4t² - 1²
D(t) = (2t + 1)² + (2t - 1)(2t + 1)
D(t) = (2t + 1)(2t + 1 + 2t - 1)
D(t) = (2t + 1)(4t)
D(t) = 4t(2t + 1)
E(x)=(5x-1)² +10x-2
E(x) = (5x - 1)² + 2(5x - 1)
E(x) = (5x - 1)(5x - 1 + 2)
E(x) = (5x - 1)(5x + 1)
F(x)=9x+6-(3x+2)²
F(x) = 3(3x + 2) - (3x + 2)²
F(x) = (3x + 2)(3 - 3x - 2)
F(x) = (3x + 2)(-3x + 1)
G(x)=(2x+5)(2-x)-2+x
G(x) = (2x + 5)(2 - x) - (2 - x)
G(x) = (2 - x)(2x + 5 - 1)
G(x) = (2 - x)(2x + 4)
G(x) = 2(2 - x)(x + 2)
Résoudre
a=4x² -1=0
(2x - 1)(2x + 1) = 0
2x - 1 = 0 ou 2x + 1 = 0
2x = 1 ou 2x = -1
x = 1/2 ou x = -1/2
b=(x-3)² -4=0
(x - 3 - 2)(x - 3 + 2) = 0
(x - 5)(x - 1) = 0
x - 5 = 0 ou x - 1 = 0
x = 5 ou x = 1
