bonjour
k (x) = - 4 x + 1
k ( 0) = 1
- 4 x + 1 = 5
- 4 x = 4
x = - 1
k (3) = - 12 + 1 = - 11
- 4 x + 1 = 9
- 4 x = 8
x = - 2
k ( -2) = 9
f (x) = x + 2 = affine
f ( - 2) = 0 donc courbe d 2
g( x ) = x + 1 = affine
g ( 0 ) = 1 donc d 3
h (x) = 1.5 x = linéaire
h ( 0) = 0 donc d 1
f(x) = 2 x
f (-1) = - 2
f ( 0 ) = 0
f (1) = 2
f (2) = 4
fais pareil avec f(x) = - 0.4 x + 0.5
