coucou
a = 4(x+y)
b = 6(x+2)
c = (x-3)(5+3)
d = (2x+3)(4+10)
e = (3x+6)(3-5)
f = (x+5)(2+9)
g = (3x+7)(2x+6)
h = (2x+1)(x+2)
i = (x+1)(7+3x)
j = (2x-2)(4x+5-3x-1) = (2x-2)(x+4)
k = (3x+2)(x-4-4x-5) = (3x+2)(-3x-9)
l = (x+1)(3-2x-3+4x) = (x+1)2x
m = 3x^2 +2x +3x+2+6x-2x^2+6-2x
m = x^2 +9x+8
beta = b^2-4ac
beta = 9^2-4*1*8
beta = 49
beta > O donc il y a deux solutions
x1 = (-9-7)/2 = -8
x2 = (-9+7)/2 = -1
donc m = (x+8)(x+1)
voila j espere t avoir aider
