3x - x² < 0
x(3-x)<0
x < 0 ou 3-x<0 donc x>-3
(x-1)²-(3x+2)(x-1) >= 0
(x-1)[(x-1)-(3x+2)] >= 0
(x-1)(x-1-3x-2) >=0
(x-1)(-2x-3) >= 0
x-1 >= 0 ou -2x-3 >= 0
x >= 1 -2x >= 3 donc x <= (-3/2)
(2x-3)² - (4x +2)² > 0
A² - B² = (a-b)(a+b) = 3 e identité remarquable
(2x-3-4x-2)(2x-3+4x+2) > 0
(-2x-5)(6x-1) > 0
-2x-5>0 6x-1>0
-2x>5 6x>1
x<(-5/2) x>(1/6)
