Bonsoir
♧1. On a :
x = 360° - ABL - BAC - ACL
x = 360° - 126,48° - 145,34° - 86,88°
x = 1,3°
♧2.
--> On a :
● h1 = 6 370 × sin 52,52° ≈ 5 055,01 km
● h2 = = 6 370 × sin 34,36° ≈ 3 595,2 km
--> D'où :
HL = BH
/tan BHL
HL = ((5055+3595)÷2/(tan1,3°÷2)
HL = (4325,105)/(tan0,65°)
HL ≈ 381 230 km
Voilà ^^
