Bonjour,
1)
n*A=n*1925=n*5²*11*7
n=11*7
2)
J'ai corrigé mon erreur. Merci.
[tex]Comme\ 12=12*1=6*2=4*3\\x^2-4y^2=12\\\\x\geq y\\(x-2y)(x+2y) =12\\\\12=12*1\\\\\left \{ {{x-2y=1} \atop {x+2y=12}} \right.\\\left \{ {{2x=13} \atop {4y=11}} \right.\\\\Pas\ de\ solution\ dans\ \mathbb{N}\\12=6*2\\\left \{ {{x-2y=2} \atop {x+2y=6}} \right.\\\left \{ {{2x=8} \atop {4y=4}} \right.\\\\\left \{ {{x=4} \atop {y=1}} \right.\\\\Solution\ (4;1)\\Preuve:\ 4^2-4*1^2=16-4=12\\\\[/tex]
[tex]12=4*3\\\\\left \{ {{x-2y=3} \atop {x+2y=4}} \right.\\\left \{ {{2x=7} \atop {4y=1}} \right.\\\\Pas\ de\ solution\ dans\ \mathbb{N}\\[/tex]
