Bonjour,
[tex](2 - 3x) {}^{2} = 1[/tex]
[tex]4 - 12x + 9 {x}^{2} = 1[/tex]
[tex]9 {x}^{2} - 12x + 3 = 0[/tex]
[tex]3(3 {x}^{2} - 4x + 1) = 0[/tex]
Donc 2 racines :
a = 3 b = -4 c = 1
∆ = b^2 - 4ac
[tex] \delta = 16 - 4 \times 3 \times 1[/tex]
[tex] = 16 - 12 = 4[/tex]
[tex] \sqrt{4} = 2[/tex]
X1 = (-b -✓∆)/2a
= (4 - 2)/6
= 2/6 => 1/3
X2 = (-b + ✓∆)/2a
=( 4+2 ) /6
= 6/6 => 1
S : { 1/3 , 1 }
