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Bonjour, Je vous demanderais de m'aider

A(x)=2(x + 3 )+ 6 + 2x

1. Factoriser A(x)
2.Développer A(x)
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g(x)=(1 - x)² - (4x - 7)

1.Développer g(x)
2.Factoriser g(x)
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f(x) = x(x + 2) - (2x - 1)(x + 1 )
g(x) = (2x + 3)² - (x + 1)²

1.Développer f(x) et g(x)
2.Factoriser f(x) et g(x)


Merci d'avance .


Répondre :

bonjour

a(x) = 2 ( x + 3) + 6 + 2 x
a(x) = 2 ( x + 3) + 2 ( 3 + x) ⇒ tu termines

a(x) = 2 x + 6 + 6 + 2 x = 4 x + 12 


g(x) = ( 1 - x)² - ( 4 x - 7) 
g(x) = 1 - 2 x + x² - 4 x - 7 = x² - 6 x - 6 

g(x) = ( 1 - x) ( 1 - x - 4 x + 7) = ( 1 -x ) ( - 5 x + 8)

tu as des exemples, continues en reconnaissant les identités

bonjour

A(x)=2(x + 3 )+ 6 + 2x

1. Factoriser A(x)

A(x)=2(x + 3 )+ 6 + 2x 

A(x)=2(x + 3 )+ 2(3+x)

a = (x+3) (2+2)

a = 4(x+3)


 2.Développer A(x)

A(x)=2(x + 3 )+ 6 + 2x 

a = 2x+6+6+2x

a = 4x+12

 -------------------------
g(x)=(1 - x)² - (4x - 7)

1.Développer g(x)

g(x)=(1 - x)² - (4x - 7) ²

g = 1-2x+x²- (16x²-56x+49)

g =1-2x+x²-16x²+56x-49

g =-15x²+54x-48


 2.Factoriser g(x)

g(x)=(1 - x)² - (4x - 7) ²

(1-x-4x+7)(1-x+4x+7)

(-5x+8)(3x+8)
 -------------------------
f(x) = x(x + 2) - (2x - 1)(x + 1 )
g(x) = (2x + 3)² - (x + 1)²

1.Développer f(x) et g(x)

f(x) = x(x + 2) - (2x - 1)(x + 1 )

f = x²+2x -(2x²+2x-x-1)

f = x²+2x-2x²-x+1

f = -x²+x+1
 

g(x) = (2x + 3)² - (x + 1)² 

g = 4x²+12x+9 -(x²+2x+1)

g =4x²+12x+9-x²-2x-1

g =3x²+10x+8

 2.Factoriser f(x) et g(x)

f(x) = x(x + 2) - (2x - 1)(x + 1 )

f = -x²+x+1

je ne vois pas comment factoriser


 g(x) = (2x + 3)² - (x + 1)²

(2x+3-x-1)(2x+3+x+1)

(x+2)(3x+4)