Réponse :
Bonsoir,
Explications étape par étape
[tex]\left\{ \begin{array}{ccc}4a+2b&=&4\\2a^2+b^2&=&4\\\end{array}\right.\\\\\\\left\{ \begin{array}{ccc}2a+b&=&2\\2a^2+b^2&=&4\\\end{array}\right.\\\\\\\left\{ \begin{array}{ccc}b&=&2-2a\\2a(3a-4)&=&0\\\end{array}\right.\\\\\\\left\{ \begin{array}{ccc}a&=&0\\b&=&2\\\end{array}\right.\qquad\ ou\ \boxed{\left\{ \begin{array}{ccc}a&=&\dfrac{4}{3}\\\\b&=&-\dfrac{2}{3} \\\end{array}\right.}[/tex]
